ArrayObject::offsetGet()

(PHP 5, PHP 7)

Returns the value at the specified index

说明

参数

The index with the value.

返回值

The value at the specified index orNULL.

错误／异常

Produces anE_NOTICEerror message when the specified index does not exist.

范例

ArrayObject::offsetGet()example

以上例程会输出：

int(7)
string(4) "e.g."
bool(false)

It's worth noting that the PHP devs *did* fix the issue brought up in Sam's comment in 2013 (per the comment thread in his link here: https://bugs.php.net/bug.php?id=34783#1366088374), since at least PHP 5.3.8.
So, you *can* (and in most cases should) overload offsetGet with reference syntax to get expected functionality:

If you're overloading ArrayObject, it's worth noting that while this method (when implemented by the parent) will return a reference, so code like $fakeArray['foobar']['hello'] = 1; will work like you expect.
However, when you overload the offsetGet method, you CANNOT define it as &offsetGet, so the above code falls out (because it returns the 'foobar' variable before you actually work with it).
This is something that the developers broke between 5.0 and 5.1, and was closed as bogus (http://bugs.php.net/bug.php?id=34783). So this is not a big, or question, or request, but just something worth noting.

Speaking of offsetGet() method overloading, be advised, that if you're iterating through Object via foreach, this method wouldn't be called. Iterator's current() method will be called instead.